9. Write a function iovert( x, p, 0) that returns x with the obits that begin at position p inverted. You can assume that x, p and 0 are integer variables and that the function will return an integer. As an example, if x = 181 [decimal] which is 10110101 in binary, and p = 4 and 0 = 2, then the function will return 101Q!101 or 173 [decimal]. The underlined bits are the changed bits. Note that bit positions are counted from the right to the left and that the counts start with a O. Therefore, position 4 is the 5th bit from the right values

#include<stdio.h>

#include<conio.h>

#include<math.h> main()

{

int invert(int,int,int); int x,n,p;

clrscr();

printf("enter any number x="); scanf("%d",&x);

printf("enter any number n="); scanf("%d",&n);

printf("enter any number p="); scanf("%d",&p);

x=invert(x,p,n);

printf("\n %d",x); getch();

return 0;

}

int invert(int x,int p,int n)

{

int i,ct=0,b[100],y,sum=0; while( x != 1 )

{

y=x%2; b[ct]=y; ct++; x=x/2;

}

b[ct]=x; for(i=ct;i>=0;i--)

printf("%d",b[i]);

for(i=p;n!=0;i--)

{

if ( b[i]==0 )

b[i]=1;

else b[i]=0;

n--;

}

printf("\n");

for (i=ct;i>=0;i--)

printf("%d",b[i]); for(i=0;i<=ct;i++) sum=sum+b[i]*pow(2,i); return sum;

}